### Cube polywell, force on coils

As the coils generate an opposing magnetic field there will be force on the coils pushing them apart. We try to calculate this force against an individual coil. We use the Lorentz force equation on a wire segment. This can also be used to calculate the torque on a coil (in case of misalignments). We treat the coil as a ring of current. The math looks like this:

We can numerically integrate over a coil calculating individual force and torque elements, summing them up. The r vector is a vector from the center of the coil to the given point (as the coil is symmetric). Also as the same current I is present also in the B vector we can generalize the equation against 1 ampere force k as F=k*I^2. In case the coils are perfectly aligned the force is perpendicular to the measured coil plane pointing away and the torque is zero.

Lets sample some configurations.

 RADIUS(R)[m] SPACING(S)[m] k(F=k*I^2) F(I=10000A)[N] F(I=50000A)[N] F(I=100000A)[N] 0.15 0.08 9.24698e-07 92 2312 9246 0.3 0.1 1.57079e-06 157 3927 15707 1.0 0.2 2.53945e-06 254 6349 25395

What about torque. Lets take an example when the measured coil is misaligned by 5 degrees (around its center).